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g^2=49/64
We move all terms to the left:
g^2-(49/64)=0
We add all the numbers together, and all the variables
g^2-(+49/64)=0
We get rid of parentheses
g^2-49/64=0
We multiply all the terms by the denominator
g^2*64-49=0
Wy multiply elements
64g^2-49=0
a = 64; b = 0; c = -49;
Δ = b2-4ac
Δ = 02-4·64·(-49)
Δ = 12544
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$g_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$g_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{12544}=112$$g_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-112}{2*64}=\frac{-112}{128} =-7/8 $$g_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+112}{2*64}=\frac{112}{128} =7/8 $
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